Base | Representation |
---|---|
bin | 1100110110001000001010… |
… | …1100111111111011111111 |
3 | 1212000020122000001021111102 |
4 | 3031202002230333323333 |
5 | 3322402021044203201 |
6 | 50012255152243315 |
7 | 2655300003133631 |
oct | 315420254777377 |
9 | 55006560037442 |
10 | 14124045303551 |
11 | 4555a793a7187 |
12 | 170140224053b |
13 | 7b5b79262551 |
14 | 36b870b5ca51 |
15 | 1975eb0c726b |
hex | cd882b3feff |
14124045303551 has 2 divisors, whose sum is σ = 14124045303552. Its totient is φ = 14124045303550.
The previous prime is 14124045303443. The next prime is 14124045303581. The reversal of 14124045303551 is 15530354042141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14124045303551 is a prime.
It is a super-2 number, since 2×141240453035512 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14124045303581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062022651775 + 7062022651776.
It is an arithmetic number, because the mean of its divisors is an integer number (7062022651776).
Almost surely, 214124045303551 is an apocalyptic number.
14124045303551 is a deficient number, since it is larger than the sum of its proper divisors (1).
14124045303551 is an equidigital number, since it uses as much as digits as its factorization.
14124045303551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 14124045303551 its reverse (15530354042141), we get a palindrome (29654399345692).
The spelling of 14124045303551 in words is "fourteen trillion, one hundred twenty-four billion, forty-five million, three hundred three thousand, five hundred fifty-one".
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