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14124045303551 is a prime number
BaseRepresentation
bin1100110110001000001010…
…1100111111111011111111
31212000020122000001021111102
43031202002230333323333
53322402021044203201
650012255152243315
72655300003133631
oct315420254777377
955006560037442
1014124045303551
114555a793a7187
12170140224053b
137b5b79262551
1436b870b5ca51
151975eb0c726b
hexcd882b3feff

14124045303551 has 2 divisors, whose sum is σ = 14124045303552. Its totient is φ = 14124045303550.

The previous prime is 14124045303443. The next prime is 14124045303581. The reversal of 14124045303551 is 15530354042141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14124045303551 is a prime.

It is a super-2 number, since 2×141240453035512 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14124045303581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062022651775 + 7062022651776.

It is an arithmetic number, because the mean of its divisors is an integer number (7062022651776).

Almost surely, 214124045303551 is an apocalyptic number.

14124045303551 is a deficient number, since it is larger than the sum of its proper divisors (1).

14124045303551 is an equidigital number, since it uses as much as digits as its factorization.

14124045303551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 14124045303551 its reverse (15530354042141), we get a palindrome (29654399345692).

The spelling of 14124045303551 in words is "fourteen trillion, one hundred twenty-four billion, forty-five million, three hundred three thousand, five hundred fifty-one".