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141241040111 = 473005128513
BaseRepresentation
bin1000001110001010011…
…1110011110011101111
3111111120022221020201202
42003202213303303233
54303230201240421
6144515113400115
713130041014023
oct2034247636357
9444508836652
10141241040111
1154999980a26
122345940903b
131041ba25562
146b9c3a2383
153a19b6710b
hex20e29f3cef

141241040111 has 4 divisors (see below), whose sum is σ = 144246168672. Its totient is φ = 138235911552.

The previous prime is 141241040099. The next prime is 141241040153. The reversal of 141241040111 is 111040142141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141241040111 - 230 = 140167298287 is a prime.

It is a super-2 number, since 2×1412410401112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141241040191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1502564210 + ... + 1502564303.

It is an arithmetic number, because the mean of its divisors is an integer number (36061542168).

Almost surely, 2141241040111 is an apocalyptic number.

141241040111 is a deficient number, since it is larger than the sum of its proper divisors (3005128561).

141241040111 is an equidigital number, since it uses as much as digits as its factorization.

141241040111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3005128560.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 141241040111 its reverse (111040142141), we get a palindrome (252281182252).

The spelling of 141241040111 in words is "one hundred forty-one billion, two hundred forty-one million, forty thousand, one hundred eleven".

Divisors: 1 47 3005128513 141241040111