14124333521 has 2 divisors, whose sum is σ = 14124333522. Its totient is φ = 14124333520.

The previous prime is 14124333493. The next prime is 14124333523. The reversal of 14124333521 is 12533342141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13424466496 + 699867025 = 115864^2 + 26455^2 .

It is a cyclic number.

It is not a de Polignac number, because 14124333521 - 2²² = 14120139217 is a prime.

Together with 14124333523, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14124333523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062166760 + 7062166761.

It is an arithmetic number, because the mean of its divisors is an integer number (7062166761).

Almost surely, 2^14124333521 is an apocalyptic number.

It is an amenable number.

14124333521 is a deficient number, since it is larger than the sum of its proper divisors (1).

14124333521 is an equidigital number, since it uses as much as digits as its factorization.

14124333521 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8640, while the sum is 29.

Adding to 14124333521 its reverse (12533342141), we get a palindrome (26657675662).

The spelling of 14124333521 in words is "fourteen billion, one hundred twenty-four million, three hundred thirty-three thousand, five hundred twenty-one".