141244000031 has 4 divisors (see below), whose sum is σ = 141252402792. Its totient is φ = 141235597272.

The previous prime is 141244000019. The next prime is 141244000123. The reversal of 141244000031 is 130000442141.

141244000031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 130000442141 = 10223 ⋅12716467.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141244000031 is a prime.

It is a super-2 number, since 2×141244000031² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141243999967 and 141244000012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141274000031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4176116 + ... + 4209801.

It is an arithmetic number, because the mean of its divisors is an integer number (35313100698).

Almost surely, 2^141244000031 is an apocalyptic number.

141244000031 is a deficient number, since it is larger than the sum of its proper divisors (8402761).

141244000031 is an equidigital number, since it uses as much as digits as its factorization.

141244000031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8402760.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 141244000031 its reverse (130000442141), we get a palindrome (271244442172).

The spelling of 141244000031 in words is "one hundred forty-one billion, two hundred forty-four million, thirty-one", and thus it is an aban number.