Base | Representation |
---|---|
bin | 10100100011011100001… |
… | …011100110110011011010 |
3 | 12000000202121021002101202 |
4 | 110203130023212303122 |
5 | 141120140441200010 |
6 | 3000511213514202 |
7 | 204021442661516 |
oct | 24433413466332 |
9 | 5000677232352 |
10 | 1412443303130 |
11 | 4a5017471092 |
12 | 1a98a84a2962 |
13 | a3267862132 |
14 | 4c511061146 |
15 | 26b1a7996a5 |
hex | 148dc2e6cda |
1412443303130 has 32 divisors (see below), whose sum is σ = 2547574406928. Its totient is φ = 563827392000.
The previous prime is 1412443303129. The next prime is 1412443303133. The reversal of 1412443303130 is 313033442141.
It is a happy number.
It can be written as a sum of positive squares in 8 ways, for example, as 643487939329 + 768955363801 = 802177^2 + 876901^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1412443303093 and 1412443303102.
It is not an unprimeable number, because it can be changed into a prime (1412443303133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32985014 + ... + 33027806.
Almost surely, 21412443303130 is an apocalyptic number.
1412443303130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1412443303130 is a deficient number, since it is larger than the sum of its proper divisors (1135131103798).
1412443303130 is a wasteful number, since it uses less digits than its factorization.
1412443303130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49442.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 1412443303130 its reverse (313033442141), we get a palindrome (1725476745271).
The spelling of 1412443303130 in words is "one trillion, four hundred twelve billion, four hundred forty-three million, three hundred three thousand, one hundred thirty".
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