Base | Representation |
---|---|
bin | 10100100011011100001… |
… | …111001001001000000111 |
3 | 12000000202200000012000212 |
4 | 110203130033021020013 |
5 | 141120141210331101 |
6 | 3000511245430035 |
7 | 204021453602303 |
oct | 24433417111007 |
9 | 5000680005025 |
10 | 1412444230151 |
11 | 4a5017a44619 |
12 | 1a98a886b31b |
13 | a3267ac8076 |
14 | 4c511222d03 |
15 | 26b1a8ce1bb |
hex | 148dc3c9207 |
1412444230151 has 2 divisors, whose sum is σ = 1412444230152. Its totient is φ = 1412444230150.
The previous prime is 1412444230139. The next prime is 1412444230177. The reversal of 1412444230151 is 1510324442141.
It is a weak prime.
It is an emirp because it is prime and its reverse (1510324442141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1412444230151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412444235151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706222115075 + 706222115076.
It is an arithmetic number, because the mean of its divisors is an integer number (706222115076).
Almost surely, 21412444230151 is an apocalyptic number.
1412444230151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412444230151 is an equidigital number, since it uses as much as digits as its factorization.
1412444230151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 1412444230151 its reverse (1510324442141), we get a palindrome (2922768672292).
The spelling of 1412444230151 in words is "one trillion, four hundred twelve billion, four hundred forty-four million, two hundred thirty thousand, one hundred fifty-one".
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