Base | Representation |
---|---|
bin | 1100110110001001111100… |
… | …1111001000001100111111 |
3 | 1212000021212100211012111222 |
4 | 3031202133033020030333 |
5 | 3322404011121343401 |
6 | 50012414452503555 |
7 | 2655314605113254 |
oct | 315423717101477 |
9 | 55007770735458 |
10 | 14124524012351 |
11 | 45561a4641195 |
12 | 170151661abbb |
13 | 7b5c244a15ac |
14 | 36b8b857142b |
15 | 197628136c1b |
hex | cd89f3c833f |
14124524012351 has 2 divisors, whose sum is σ = 14124524012352. Its totient is φ = 14124524012350.
The previous prime is 14124524012243. The next prime is 14124524012449. The reversal of 14124524012351 is 15321042542141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14124524012351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14124524015351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062262006175 + 7062262006176.
It is an arithmetic number, because the mean of its divisors is an integer number (7062262006176).
Almost surely, 214124524012351 is an apocalyptic number.
14124524012351 is a deficient number, since it is larger than the sum of its proper divisors (1).
14124524012351 is an equidigital number, since it uses as much as digits as its factorization.
14124524012351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 14124524012351 its reverse (15321042542141), we get a palindrome (29445566554492).
The spelling of 14124524012351 in words is "fourteen trillion, one hundred twenty-four billion, five hundred twenty-four million, twelve thousand, three hundred fifty-one".
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