Base | Representation |
---|---|
bin | 1100110110001011101111… |
… | …0011010000010000001011 |
3 | 1212000100002202120201111212 |
4 | 3031202323303100100023 |
5 | 3322411001312311210 |
6 | 50012534212243335 |
7 | 2655332514402560 |
oct | 315427363202013 |
9 | 55010082521455 |
10 | 14125003244555 |
11 | 4556420103465 |
12 | 170162b01054b |
13 | 7b5c9c864948 |
14 | 36b92207c867 |
15 | 19765524b805 |
hex | cd8bbcd040b |
14125003244555 has 16 divisors (see below), whose sum is σ = 19374728325120. Its totient is φ = 9684068858592.
The previous prime is 14125003244551. The next prime is 14125003244567. The reversal of 14125003244555 is 55544230052141.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 14125003244555 - 22 = 14125003244551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14125003244551) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34117379 + ... + 34528908.
It is an arithmetic number, because the mean of its divisors is an integer number (1210920520320).
Almost surely, 214125003244555 is an apocalyptic number.
14125003244555 is a deficient number, since it is larger than the sum of its proper divisors (5249725080565).
14125003244555 is an equidigital number, since it uses as much as digits as its factorization.
14125003244555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68652178.
The product of its (nonzero) digits is 480000, while the sum is 41.
Adding to 14125003244555 its reverse (55544230052141), we get a palindrome (69669233296696).
The spelling of 14125003244555 in words is "fourteen trillion, one hundred twenty-five billion, three million, two hundred forty-four thousand, five hundred fifty-five".
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