14125043000141 has 2 divisors, whose sum is σ = 14125043000142. Its totient is φ = 14125043000140.

The previous prime is 14125043000021. The next prime is 14125043000147. The reversal of 14125043000141 is 14100034052141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13474405562500 + 650637437641 = 3670750^2 + 806621^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14125043000141 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14125043000141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14125043000147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062521500070 + 7062521500071.

It is an arithmetic number, because the mean of its divisors is an integer number (7062521500071).

Almost surely, 2^{14125043000141} is an apocalyptic number.

It is an amenable number.

14125043000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14125043000141 is an equidigital number, since it uses as much as digits as its factorization.

14125043000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 26.

Adding to 14125043000141 its reverse (14100034052141), we get a palindrome (28225077052282).

The spelling of 14125043000141 in words is "fourteen trillion, one hundred twenty-five billion, forty-three million, one hundred forty-one", and thus it is an aban number.