Base | Representation |
---|---|
bin | 1000001110001100101… |
… | …1101010111110100111 |
3 | 111111120222121212111112 |
4 | 2003203023222332213 |
5 | 4303240103104002 |
6 | 144520051055235 |
7 | 13130213640155 |
oct | 2034313527647 |
9 | 444528555445 |
10 | 141250441127 |
11 | 549a4212064 |
12 | 234605a151b |
13 | 104209675a3 |
14 | 6b9d72c3d5 |
15 | 3a1a8c2852 |
hex | 20e32eafa7 |
141250441127 has 2 divisors, whose sum is σ = 141250441128. Its totient is φ = 141250441126.
The previous prime is 141250441103. The next prime is 141250441141. The reversal of 141250441127 is 721144052141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141250441127 - 26 = 141250441063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141250441093 and 141250441102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141250441147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70625220563 + 70625220564.
It is an arithmetic number, because the mean of its divisors is an integer number (70625220564).
Almost surely, 2141250441127 is an apocalyptic number.
141250441127 is a deficient number, since it is larger than the sum of its proper divisors (1).
141250441127 is an equidigital number, since it uses as much as digits as its factorization.
141250441127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8960, while the sum is 32.
Adding to 141250441127 its reverse (721144052141), we get a palindrome (862394493268).
The spelling of 141250441127 in words is "one hundred forty-one billion, two hundred fifty million, four hundred forty-one thousand, one hundred twenty-seven".
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