Base | Representation |
---|---|
bin | 1100110110001100001011… |
… | …1100001000011011001100 |
3 | 1212000100102002221112222021 |
4 | 3031203002330020123030 |
5 | 3322411222442343200 |
6 | 50012554131255524 |
7 | 2655335500405636 |
oct | 315430274103314 |
9 | 55010362845867 |
10 | 14125123012300 |
11 | 4556481776773 |
12 | 170166314a5a4 |
13 | 7b5cbb609c31 |
14 | 36b933d37a56 |
15 | 197660a0841a |
hex | cd8c2f086cc |
14125123012300 has 18 divisors (see below), whose sum is σ = 30651516936908. Its totient is φ = 5650049204880.
The previous prime is 14125123012271. The next prime is 14125123012327. The reversal of 14125123012300 is 321032152141.
It is a super-2 number, since 2×141251230123002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 70625614962 + ... + 70625615161.
Almost surely, 214125123012300 is an apocalyptic number.
14125123012300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14125123012300 is an abundant number, since it is smaller than the sum of its proper divisors (16526393924608).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14125123012300 is a wasteful number, since it uses less digits than its factorization.
14125123012300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 141251230137 (or 141251230130 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 14125123012300 its reverse (321032152141), we get a palindrome (14446155164441).
The spelling of 14125123012300 in words is "fourteen trillion, one hundred twenty-five billion, one hundred twenty-three million, twelve thousand, three hundred".
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