Base | Representation |
---|---|
bin | 1100110110001101001111… |
… | …0101101101101001100011 |
3 | 1212000101010212110101012101 |
4 | 3031203103311231221203 |
5 | 3322412313033324220 |
6 | 50013042220311231 |
7 | 2655345512361256 |
oct | 315432365555143 |
9 | 55011125411171 |
10 | 14125406542435 |
11 | 45566078210a1 |
12 | 17017220a2517 |
13 | 7b603528c346 |
14 | 36b95d86109d |
15 | 19767a86230a |
hex | cd8d3d6da63 |
14125406542435 has 4 divisors (see below), whose sum is σ = 16950487850928. Its totient is φ = 11300325233944.
The previous prime is 14125406542427. The next prime is 14125406542439. The reversal of 14125406542435 is 53424560452141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14125406542435 - 23 = 14125406542427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14125406542439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1412540654239 + ... + 1412540654248.
It is an arithmetic number, because the mean of its divisors is an integer number (4237621962732).
Almost surely, 214125406542435 is an apocalyptic number.
14125406542435 is a deficient number, since it is larger than the sum of its proper divisors (2825081308493).
14125406542435 is an equidigital number, since it uses as much as digits as its factorization.
14125406542435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2825081308492.
The product of its (nonzero) digits is 2304000, while the sum is 46.
Adding to 14125406542435 its reverse (53424560452141), we get a palindrome (67549966994576).
The spelling of 14125406542435 in words is "fourteen trillion, one hundred twenty-five billion, four hundred six million, five hundred forty-two thousand, four hundred thirty-five".
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