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14125455343481 is a prime number
BaseRepresentation
bin1100110110001101011010…
…1111110111111101111001
31212000101021021021201122112
43031203112233313331321
53322412413031442411
650013051122302105
72655346644233336
oct315432657677571
955011237251575
1014125455343481
114556632323039
1217017364b7935
137b6042417ac1
1436b96612598d
1519767eca1b8b
hexcd8d6bf7f79

14125455343481 has 2 divisors, whose sum is σ = 14125455343482. Its totient is φ = 14125455343480.

The previous prime is 14125455343471. The next prime is 14125455343513. The reversal of 14125455343481 is 18434355452141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13831890765625 + 293564577856 = 3719125^2 + 541816^2 .

It is a cyclic number.

It is not a de Polignac number, because 14125455343481 - 214 = 14125455327097 is a prime.

It is a super-2 number, since 2×141254553434812 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (14125455343471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062727671740 + 7062727671741.

It is an arithmetic number, because the mean of its divisors is an integer number (7062727671741).

Almost surely, 214125455343481 is an apocalyptic number.

It is an amenable number.

14125455343481 is a deficient number, since it is larger than the sum of its proper divisors (1).

14125455343481 is an equidigital number, since it uses as much as digits as its factorization.

14125455343481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4608000, while the sum is 50.

The spelling of 14125455343481 in words is "fourteen trillion, one hundred twenty-five billion, four hundred fifty-five million, three hundred forty-three thousand, four hundred eighty-one".