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14125455343513 is a prime number
BaseRepresentation
bin1100110110001101011010…
…1111110111111110011001
31212000101021021021201200201
43031203112233313332121
53322412413031443023
650013051122302201
72655346644233413
oct315432657677631
955011237251621
1014125455343513
114556632323068
1217017364b7961
137b6042417b17
1436b9661259b3
1519767eca1bad
hexcd8d6bf7f99

14125455343513 has 2 divisors, whose sum is σ = 14125455343514. Its totient is φ = 14125455343512.

The previous prime is 14125455343481. The next prime is 14125455343541. The reversal of 14125455343513 is 31534355452141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9583284193344 + 4542171150169 = 3095688^2 + 2131237^2 .

It is an emirp because it is prime and its reverse (31534355452141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14125455343513 - 25 = 14125455343481 is a prime.

It is not a weakly prime, because it can be changed into another prime (14125455343553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062727671756 + 7062727671757.

It is an arithmetic number, because the mean of its divisors is an integer number (7062727671757).

Almost surely, 214125455343513 is an apocalyptic number.

It is an amenable number.

14125455343513 is a deficient number, since it is larger than the sum of its proper divisors (1).

14125455343513 is an equidigital number, since it uses as much as digits as its factorization.

14125455343513 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2160000, while the sum is 46.

The spelling of 14125455343513 in words is "fourteen trillion, one hundred twenty-five billion, four hundred fifty-five million, three hundred forty-three thousand, five hundred thirteen".