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1412845003 is a prime number
BaseRepresentation
bin101010000110110…
…0100110111001011
310122110111221222201
41110031210313023
510343142020003
6352110101031
750003661433
oct12415446713
93573457881
101412845003
116655723a9
123351aa777
1319692827b
14d58d72c3
1584080b1d
hex54364dcb

1412845003 has 2 divisors, whose sum is σ = 1412845004. Its totient is φ = 1412845002.

The previous prime is 1412845001. The next prime is 1412845019. The reversal of 1412845003 is 3005482141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1412845003 - 21 = 1412845001 is a prime.

It is a super-2 number, since 2×14128450032 = 3992262005004140018, which contains 22 as substring.

Together with 1412845001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1412845001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706422501 + 706422502.

It is an arithmetic number, because the mean of its divisors is an integer number (706422502).

Almost surely, 21412845003 is an apocalyptic number.

1412845003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412845003 is an equidigital number, since it uses as much as digits as its factorization.

1412845003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 28.

The square root of 1412845003 is about 37587.8305173363. The cubic root of 1412845003 is about 1122.0998560195.

The spelling of 1412845003 in words is "one billion, four hundred twelve million, eight hundred forty-five thousand, three".