Base | Representation |
---|---|
bin | 1100110110011110011001… |
… | …0010110000010001010101 |
3 | 1212000211000202202202220122 |
4 | 3031213212102300101111 |
5 | 3323001230321100113 |
6 | 50015123144241325 |
7 | 2655600563520011 |
oct | 315474622602125 |
9 | 55024022682818 |
10 | 14130011112533 |
11 | 455855a9a4828 |
12 | 17025a8170245 |
13 | 7b65ba219834 |
14 | 36bc791cb541 |
15 | 197849c09408 |
hex | cd9e64b0455 |
14130011112533 has 4 divisors (see below), whose sum is σ = 14133872830080. Its totient is φ = 14126149394988.
The previous prime is 14130011112527. The next prime is 14130011112583. The reversal of 14130011112533 is 33521111003141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14130011112533 - 232 = 14125716145237 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14130011112583) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1930853285 + ... + 1930860602.
It is an arithmetic number, because the mean of its divisors is an integer number (3533468207520).
Almost surely, 214130011112533 is an apocalyptic number.
It is an amenable number.
14130011112533 is a deficient number, since it is larger than the sum of its proper divisors (3861717547).
14130011112533 is an equidigital number, since it uses as much as digits as its factorization.
14130011112533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3861717546.
The product of its (nonzero) digits is 1080, while the sum is 26.
Adding to 14130011112533 its reverse (33521111003141), we get a palindrome (47651122115674).
The spelling of 14130011112533 in words is "fourteen trillion, one hundred thirty billion, eleven million, one hundred twelve thousand, five hundred thirty-three".
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