141301320241041 has 12 divisors (see below), whose sum is σ = 204122109255168. Its totient is φ = 94191556049784.

The previous prime is 141301320241013. The next prime is 141301320241099. The reversal of 141301320241041 is 140142023103141.

It is a happy number.

141301320241041 is a `hidden beast` number, since 1 + 4 + 1 + 3 + 0 + 1 + 3 + 202 + 410 + 41 = 666.

141301320241041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 141301320241041 - 2¹¹ = 141301320238993 is a prime.

It is a super-2 number, since 2×141301320241041² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141301320240996 and 141301320241014.

It is not an unprimeable number, because it can be changed into a prime (141301320241241) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 776913265 + ... + 777095118.

It is an arithmetic number, because the mean of its divisors is an integer number (17010175771264).

Almost surely, 2^{141301320241041} is an apocalyptic number.

It is an amenable number.

141301320241041 is a deficient number, since it is larger than the sum of its proper divisors (62820789014127).

141301320241041 is a wasteful number, since it uses less digits than its factorization.

141301320241041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1554018492 (or 1554018489 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 141301320241041 its reverse (140142023103141), we get a palindrome (281443343344182).

The spelling of 141301320241041 in words is "one hundred forty-one trillion, three hundred one billion, three hundred twenty million, two hundred forty-one thousand, forty-one".