Base | Representation |
---|---|
bin | 10100100011111110100… |
… | …100110101001111100011 |
3 | 12000002020211001122211211 |
4 | 110203332210311033203 |
5 | 141122331201404334 |
6 | 3001044345450551 |
7 | 204041650504354 |
oct | 24437644651743 |
9 | 5002224048754 |
10 | 1413020341219 |
11 | 4a5293166373 |
12 | 1a9a297a0a57 |
13 | a332a27b3a6 |
14 | 4c56794bd2b |
15 | 26b5127da64 |
hex | 148fe9353e3 |
1413020341219 has 2 divisors, whose sum is σ = 1413020341220. Its totient is φ = 1413020341218.
The previous prime is 1413020341169. The next prime is 1413020341247. The reversal of 1413020341219 is 9121430203141.
It is a strong prime.
It is an emirp because it is prime and its reverse (9121430203141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1413020341219 - 215 = 1413020308451 is a prime.
It is a super-2 number, since 2×14130203412192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1413020341259) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706510170609 + 706510170610.
It is an arithmetic number, because the mean of its divisors is an integer number (706510170610).
Almost surely, 21413020341219 is an apocalyptic number.
1413020341219 is a deficient number, since it is larger than the sum of its proper divisors (1).
1413020341219 is an equidigital number, since it uses as much as digits as its factorization.
1413020341219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 1413020341219 in words is "one trillion, four hundred thirteen billion, twenty million, three hundred forty-one thousand, two hundred nineteen".
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