Base | Representation |
---|---|
bin | 11010010100011110… |
… | …10010000111101011 |
3 | 1100110202212211021021 |
4 | 31022033102013223 |
5 | 212414342003001 |
6 | 10254051553311 |
7 | 1010110415221 |
oct | 151217220753 |
9 | 40422784237 |
10 | 14130422251 |
11 | 5aa1289420 |
12 | 28a42bb837 |
13 | 14426448ca |
14 | 980946b11 |
15 | 57a7e6ba1 |
hex | 34a3d21eb |
14130422251 has 4 divisors (see below), whose sum is σ = 15415006104. Its totient is φ = 12845838400.
The previous prime is 14130422249. The next prime is 14130422279. The reversal of 14130422251 is 15222403141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15222403141 = 11 ⋅1383854831.
It is a cyclic number.
It is not a de Polignac number, because 14130422251 - 21 = 14130422249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14130422281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 642291910 + ... + 642291931.
It is an arithmetic number, because the mean of its divisors is an integer number (3853751526).
Almost surely, 214130422251 is an apocalyptic number.
14130422251 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14130422251 is a deficient number, since it is larger than the sum of its proper divisors (1284583853).
14130422251 is a wasteful number, since it uses less digits than its factorization.
14130422251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1284583852.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 14130422251 its reverse (15222403141), we get a palindrome (29352825392).
The spelling of 14130422251 in words is "fourteen billion, one hundred thirty million, four hundred twenty-two thousand, two hundred fifty-one".
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