Base | Representation |
---|---|
bin | 100000001000010000101010… |
… | …011000001011110100011011 |
3 | 200112022122020211001002211212 |
4 | 200020100222120023310123 |
5 | 122010120404031140324 |
6 | 1220310403300013335 |
7 | 41522646654651242 |
oct | 4010205230136433 |
9 | 615278224032755 |
10 | 141305135021339 |
11 | 4102a1979a1a23 |
12 | 13a21a6b99124b |
13 | 60b002b61c8b3 |
14 | 26c72c2843959 |
15 | 1150a0e13970e |
hex | 80842a60bd1b |
141305135021339 has 2 divisors, whose sum is σ = 141305135021340. Its totient is φ = 141305135021338.
The previous prime is 141305135021299. The next prime is 141305135021357. The reversal of 141305135021339 is 933120531503141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141305135021339 - 232 = 141300840054043 is a prime.
It is a super-3 number, since 3×1413051350213393 (a number of 43 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 141305135021296 and 141305135021305.
It is not a weakly prime, because it can be changed into another prime (141305135021839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70652567510669 + 70652567510670.
It is an arithmetic number, because the mean of its divisors is an integer number (70652567510670).
Almost surely, 2141305135021339 is an apocalyptic number.
141305135021339 is a deficient number, since it is larger than the sum of its proper divisors (1).
141305135021339 is an equidigital number, since it uses as much as digits as its factorization.
141305135021339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145800, while the sum is 41.
The spelling of 141305135021339 in words is "one hundred forty-one trillion, three hundred five billion, one hundred thirty-five million, twenty-one thousand, three hundred thirty-nine".
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