14130524450423 has 2 divisors, whose sum is σ = 14130524450424. Its totient is φ = 14130524450422.

The previous prime is 14130524450243. The next prime is 14130524450429. The reversal of 14130524450423 is 32405442503141.

Together with previous prime (14130524450243) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14130524450423 - 2⁸ = 14130524450167 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14130524450429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065262225211 + 7065262225212.

It is an arithmetic number, because the mean of its divisors is an integer number (7065262225212).

Almost surely, 2^{14130524450423} is an apocalyptic number.

14130524450423 is a deficient number, since it is larger than the sum of its proper divisors (1).

14130524450423 is an equidigital number, since it uses as much as digits as its factorization.

14130524450423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 14130524450423 its reverse (32405442503141), we get a palindrome (46535966953564).

The spelling of 14130524450423 in words is "fourteen trillion, one hundred thirty billion, five hundred twenty-four million, four hundred fifty thousand, four hundred twenty-three".