Base | Representation |
---|---|
bin | 1100110110100000010101… |
… | …0010110010001011010011 |
3 | 1212000212101000102200001020 |
4 | 3031220011102302023103 |
5 | 3323003311442322120 |
6 | 50015250524010523 |
7 | 2655616510354635 |
oct | 315500522621323 |
9 | 55025330380036 |
10 | 14130531214035 |
11 | 45587a7540785 |
12 | 1702712390a43 |
13 | 7b6670bbc2c2 |
14 | 36bcc82d6a55 |
15 | 19787a6e3640 |
hex | cda054b22d3 |
14130531214035 has 64 divisors (see below), whose sum is σ = 22824861696000. Its totient is φ = 7464720421760.
The previous prime is 14130531214031. The next prime is 14130531214067. The reversal of 14130531214035 is 53041213503141.
It is not a de Polignac number, because 14130531214035 - 22 = 14130531214031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14130531213987 and 14130531214005.
It is not an unprimeable number, because it can be changed into a prime (14130531214031) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 534040636 + ... + 534067094.
It is an arithmetic number, because the mean of its divisors is an integer number (356638464000).
Almost surely, 214130531214035 is an apocalyptic number.
14130531214035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14130531214035 is a deficient number, since it is larger than the sum of its proper divisors (8694330481965).
14130531214035 is a wasteful number, since it uses less digits than its factorization.
14130531214035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27496.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 14130531214035 its reverse (53041213503141), we get a palindrome (67171744717176).
The spelling of 14130531214035 in words is "fourteen trillion, one hundred thirty billion, five hundred thirty-one million, two hundred fourteen thousand, thirty-five".
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