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141310001419 is a prime number
BaseRepresentation
bin1000001110011010111…
…0111000000100001011
3111111202010200211212021
42003212232320010023
54303400330021134
6144530015425311
713131536123266
oct2034656700413
9444663624767
10141310001419
1154a248a2644
1223478525237
13104300bc372
146ba75d3cdd
153a20c3a0b4
hex20e6bb810b

141310001419 has 2 divisors, whose sum is σ = 141310001420. Its totient is φ = 141310001418.

The previous prime is 141310001377. The next prime is 141310001453. The reversal of 141310001419 is 914100013141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141310001419 - 217 = 141309870347 is a prime.

It is a super-2 number, since 2×1413100014192 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141310001393 and 141310001402.

It is not a weakly prime, because it can be changed into another prime (141310001719) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70655000709 + 70655000710.

It is an arithmetic number, because the mean of its divisors is an integer number (70655000710).

Almost surely, 2141310001419 is an apocalyptic number.

141310001419 is a deficient number, since it is larger than the sum of its proper divisors (1).

141310001419 is an equidigital number, since it uses as much as digits as its factorization.

141310001419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 141310001419 in words is "one hundred forty-one billion, three hundred ten million, one thousand, four hundred nineteen".