14131044431143 has 4 divisors (see below), whose sum is σ = 14153947259040. Its totient is φ = 14108141603248.

The previous prime is 14131044431131. The next prime is 14131044431159. The reversal of 14131044431143 is 34113444013141.

14131044431143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14131044431143 - 2¹³ = 14131044422951 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14131044431099 and 14131044431108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14131044431443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11451413023 + ... + 11451414256.

It is an arithmetic number, because the mean of its divisors is an integer number (3538486814760).

Almost surely, 2^{14131044431143} is an apocalyptic number.

14131044431143 is a deficient number, since it is larger than the sum of its proper divisors (22902827897).

14131044431143 is an equidigital number, since it uses as much as digits as its factorization.

14131044431143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22902827896.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 14131044431143 its reverse (34113444013141), we get a palindrome (48244488444284).

The spelling of 14131044431143 in words is "fourteen trillion, one hundred thirty-one billion, forty-four million, four hundred thirty-one thousand, one hundred forty-three".