1413110220113 has 2 divisors, whose sum is σ = 1413110220114. Its totient is φ = 1413110220112.

The previous prime is 1413110220091. The next prime is 1413110220133. The reversal of 1413110220113 is 3110220113141.

It is an a-pointer prime, because the next prime (1413110220133) can be obtained adding 1413110220113 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 946830194704 + 466280025409 = 973052^2 + 682847^2 .

It is an emirp because it is prime and its reverse (3110220113141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1413110220113 - 2²⁸ = 1412841784657 is a prime.

It is a super-2 number, since 2×1413110220113² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1413110220133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706555110056 + 706555110057.

It is an arithmetic number, because the mean of its divisors is an integer number (706555110057).

Almost surely, 2^{1413110220113} is an apocalyptic number.

It is an amenable number.

1413110220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413110220113 is an equidigital number, since it uses as much as digits as its factorization.

1413110220113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1413110220113 its reverse (3110220113141), we get a palindrome (4523330333254).

The spelling of 1413110220113 in words is "one trillion, four hundred thirteen billion, one hundred ten million, two hundred twenty thousand, one hundred thirteen".