Base | Representation |
---|---|
bin | 11010010100100100… |
… | …10010110100010111 |
3 | 1100110211100220222022 |
4 | 31022102102310113 |
5 | 212420042232133 |
6 | 10254120523355 |
7 | 1010120213321 |
oct | 151222226427 |
9 | 40424326868 |
10 | 14131211543 |
11 | 5aa1778429 |
12 | 28a462055b |
13 | 144285cc47 |
14 | 980ab0611 |
15 | 57a900998 |
hex | 34a492d17 |
14131211543 has 2 divisors, whose sum is σ = 14131211544. Its totient is φ = 14131211542.
The previous prime is 14131211539. The next prime is 14131211573. The reversal of 14131211543 is 34511213141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14131211543 - 22 = 14131211539 is a prime.
It is a super-2 number, since 2×141312115432 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14131211513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065605771 + 7065605772.
It is an arithmetic number, because the mean of its divisors is an integer number (7065605772).
Almost surely, 214131211543 is an apocalyptic number.
14131211543 is a deficient number, since it is larger than the sum of its proper divisors (1).
14131211543 is an equidigital number, since it uses as much as digits as its factorization.
14131211543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 26.
Adding to 14131211543 its reverse (34511213141), we get a palindrome (48642424684).
The spelling of 14131211543 in words is "fourteen billion, one hundred thirty-one million, two hundred eleven thousand, five hundred forty-three".
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