14131213333 has 2 divisors, whose sum is σ = 14131213334. Its totient is φ = 14131213332.

The previous prime is 14131213301. The next prime is 14131213357. The reversal of 14131213333 is 33331213141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12928372209 + 1202841124 = 113703^2 + 34682^2 .

It is an emirp because it is prime and its reverse (33331213141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14131213333 - 2⁵ = 14131213301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14131213298 and 14131213307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14131213373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065606666 + 7065606667.

It is an arithmetic number, because the mean of its divisors is an integer number (7065606667).

Almost surely, 2^14131213333 is an apocalyptic number.

It is an amenable number.

14131213333 is a deficient number, since it is larger than the sum of its proper divisors (1).

14131213333 is an equidigital number, since it uses as much as digits as its factorization.

14131213333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1944, while the sum is 25.

Adding to 14131213333 its reverse (33331213141), we get a palindrome (47462426474).

The spelling of 14131213333 in words is "fourteen billion, one hundred thirty-one million, two hundred thirteen thousand, three hundred thirty-three".