Base | Representation |
---|---|
bin | 11010010100100100… |
… | …10111111000101101 |
3 | 1100110211101222110010 |
4 | 31022102113320231 |
5 | 212420043413201 |
6 | 10254121203433 |
7 | 1010120330664 |
oct | 151222277055 |
9 | 40424358403 |
10 | 14131232301 |
11 | 5aa1791a8a |
12 | 28a4630579 |
13 | 1442869524 |
14 | 980ab7ddb |
15 | 57a906bd6 |
hex | 34a497e2d |
14131232301 has 4 divisors (see below), whose sum is σ = 18841643072. Its totient is φ = 9420821532.
The previous prime is 14131232281. The next prime is 14131232321. The reversal of 14131232301 is 10323213141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (14131232281) and next prime (14131232321).
It is not a de Polignac number, because 14131232301 - 29 = 14131231789 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14131232321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2355205381 + ... + 2355205386.
It is an arithmetic number, because the mean of its divisors is an integer number (4710410768).
Almost surely, 214131232301 is an apocalyptic number.
It is an amenable number.
14131232301 is a deficient number, since it is larger than the sum of its proper divisors (4710410771).
14131232301 is an equidigital number, since it uses as much as digits as its factorization.
14131232301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4710410770.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 14131232301 its reverse (10323213141), we get a palindrome (24454445442).
The spelling of 14131232301 in words is "fourteen billion, one hundred thirty-one million, two hundred thirty-two thousand, three hundred one".
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