Base | Representation |
---|---|
bin | 1000001110011011101… |
… | …0101101001001100010 |
3 | 111111202100112101122200 |
4 | 2003212322231021202 |
5 | 4303402123234214 |
6 | 144530210114030 |
7 | 13131604360200 |
oct | 2034672551142 |
9 | 444670471580 |
10 | 141313102434 |
11 | 54a26620469 |
12 | 2347957b916 |
13 | 1043093699a |
14 | 6ba7ba0070 |
15 | 3a2114dd09 |
hex | 20e6ead262 |
141313102434 has 72 divisors (see below), whose sum is σ = 356629176540. Its totient is φ = 40322745792.
The previous prime is 141313102423. The next prime is 141313102451. The reversal of 141313102434 is 434201313141.
141313102434 is a `hidden beast` number, since 1 + 413 + 1 + 3 + 1 + 0 + 243 + 4 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 95386469409 + 45926633025 = 308847^2 + 214305^2 .
It is a super-3 number, since 3×1413131024343 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 141313102398 and 141313102407.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 578152 + ... + 785420.
Almost surely, 2141313102434 is an apocalyptic number.
141313102434 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 141313102434, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (178314588270).
141313102434 is an abundant number, since it is smaller than the sum of its proper divisors (215316074106).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141313102434 is a wasteful number, since it uses less digits than its factorization.
141313102434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 208064 (or 208054 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 141313102434 its reverse (434201313141), we get a palindrome (575514415575).
The spelling of 141313102434 in words is "one hundred forty-one billion, three hundred thirteen million, one hundred two thousand, four hundred thirty-four".
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