1413132433 has 2 divisors, whose sum is σ = 1413132434. Its totient is φ = 1413132432.

The previous prime is 1413132403. The next prime is 1413132437. The reversal of 1413132433 is 3342313141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1390693264 + 22439169 = 37292^2 + 4737^2 .

It is an emirp because it is prime and its reverse (3342313141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1413132433 - 2¹³ = 1413124241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1413132398 and 1413132407.

It is not a weakly prime, because it can be changed into another prime (1413132437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706566216 + 706566217.

It is an arithmetic number, because the mean of its divisors is an integer number (706566217).

Almost surely, 2^1413132433 is an apocalyptic number.

It is an amenable number.

1413132433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413132433 is an equidigital number, since it uses as much as digits as its factorization.

1413132433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 25.

The square root of 1413132433 is about 37591.6537678246. The cubic root of 1413132433 is about 1122.1759444066.

Adding to 1413132433 its reverse (3342313141), we get a palindrome (4755445574).

It can be divided in two parts, 14131 and 32433, that added together give a palindrome (46564).

The spelling of 1413132433 in words is "one billion, four hundred thirteen million, one hundred thirty-two thousand, four hundred thirty-three".