Base | Representation |
---|---|
bin | 10100100100000101101… |
… | …101110011011000011110 |
3 | 12000002120011110201211111 |
4 | 110210011231303120132 |
5 | 141123102333232111 |
6 | 3001104305212234 |
7 | 204044633641621 |
oct | 24440555633036 |
9 | 5002504421744 |
10 | 1413140133406 |
11 | 4a5344845a81 |
12 | 1a9a6193107a |
13 | a3349031841 |
14 | 4c579811db8 |
15 | 26b5ba42a21 |
hex | 14905b7361e |
1413140133406 has 4 divisors (see below), whose sum is σ = 2119710200112. Its totient is φ = 706570066702.
The previous prime is 1413140133341. The next prime is 1413140133421. The reversal of 1413140133406 is 6043310413141.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 353285033350 + ... + 353285033353.
It is an arithmetic number, because the mean of its divisors is an integer number (529927550028).
Almost surely, 21413140133406 is an apocalyptic number.
1413140133406 is a deficient number, since it is larger than the sum of its proper divisors (706570066706).
1413140133406 is an equidigital number, since it uses as much as digits as its factorization.
1413140133406 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 706570066705.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 1413140133406 its reverse (6043310413141), we get a palindrome (7456450546547).
The spelling of 1413140133406 in words is "one trillion, four hundred thirteen billion, one hundred forty million, one hundred thirty-three thousand, four hundred six".
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