Base | Representation |
---|---|
bin | 10100100100000101111… |
… | …001111011111110011101 |
3 | 12000002120101110100020121 |
4 | 110210011321323332131 |
5 | 141123104142024313 |
6 | 3001104501314541 |
7 | 204045002660512 |
oct | 24440571737635 |
9 | 5002511410217 |
10 | 1413143314333 |
11 | 4a5346618943 |
12 | 1a9a62a05a51 |
13 | a33498a664a |
14 | 4c579ddd309 |
15 | 26b5be7028d |
hex | 14905e7bf9d |
1413143314333 has 2 divisors, whose sum is σ = 1413143314334. Its totient is φ = 1413143314332.
The previous prime is 1413143314327. The next prime is 1413143314361. The reversal of 1413143314333 is 3334133413141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1366193958649 + 46949355684 = 1168843^2 + 216678^2 .
It is a cyclic number.
It is not a de Polignac number, because 1413143314333 - 217 = 1413143183261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1413143314393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706571657166 + 706571657167.
It is an arithmetic number, because the mean of its divisors is an integer number (706571657167).
Almost surely, 21413143314333 is an apocalyptic number.
It is an amenable number.
1413143314333 is a deficient number, since it is larger than the sum of its proper divisors (1).
1413143314333 is an equidigital number, since it uses as much as digits as its factorization.
1413143314333 is an evil number, because the sum of its binary digits is even.
The product of its digits is 46656, while the sum is 34.
Adding to 1413143314333 its reverse (3334133413141), we get a palindrome (4747276727474).
The spelling of 1413143314333 in words is "one trillion, four hundred thirteen billion, one hundred forty-three million, three hundred fourteen thousand, three hundred thirty-three".
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