Search a number
-
+
14131515441311 is a prime number
BaseRepresentation
bin1100110110100011111111…
…1101010100000010011111
31212000221220121102121001022
43031220333331110002133
53323012320423110221
650015532323234355
72655653061224132
oct315507775240237
955027817377038
1014131515441311
114559162071254
121702947b189bb
137b6799a961c8
1436bd7ccda219
151978d6d0b4ab
hexcda3ff5409f

14131515441311 has 2 divisors, whose sum is σ = 14131515441312. Its totient is φ = 14131515441310.

The previous prime is 14131515441289. The next prime is 14131515441317. The reversal of 14131515441311 is 11314451513141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14131515441311 - 218 = 14131515179167 is a prime.

It is a super-2 number, since 2×141315154413112 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14131515441317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065757720655 + 7065757720656.

It is an arithmetic number, because the mean of its divisors is an integer number (7065757720656).

Almost surely, 214131515441311 is an apocalyptic number.

14131515441311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14131515441311 is an equidigital number, since it uses as much as digits as its factorization.

14131515441311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 35.

Adding to 14131515441311 its reverse (11314451513141), we get a palindrome (25445966954452).

The spelling of 14131515441311 in words is "fourteen trillion, one hundred thirty-one billion, five hundred fifteen million, four hundred forty-one thousand, three hundred eleven".