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14131554250381 is a prime number
BaseRepresentation
bin1100110110100100001001…
…0001010110111010001101
31212000222000022110022002021
43031221002101112322031
53323012410342003011
650015540231130141
72655654042132121
oct315510221267215
955028008408067
1014131554250381
114559181a69067
121702958b13951
137b67a4b33959
1436bd8411d581
151978da425471
hexcda42456e8d

14131554250381 has 2 divisors, whose sum is σ = 14131554250382. Its totient is φ = 14131554250380.

The previous prime is 14131554250279. The next prime is 14131554250423. The reversal of 14131554250381 is 18305245513141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9902633454025 + 4228920796356 = 3146845^2 + 2056434^2 .

It is a cyclic number.

It is not a de Polignac number, because 14131554250381 - 213 = 14131554242189 is a prime.

It is a super-2 number, since 2×141315542503812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14131554250481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065777125190 + 7065777125191.

It is an arithmetic number, because the mean of its divisors is an integer number (7065777125191).

Almost surely, 214131554250381 is an apocalyptic number.

It is an amenable number.

14131554250381 is a deficient number, since it is larger than the sum of its proper divisors (1).

14131554250381 is an equidigital number, since it uses as much as digits as its factorization.

14131554250381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 43.

The spelling of 14131554250381 in words is "fourteen trillion, one hundred thirty-one billion, five hundred fifty-four million, two hundred fifty thousand, three hundred eighty-one".