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14132104023 = 334611361081
BaseRepresentation
bin11010010100101011…
…01100101101010111
31100110220001021020010
431022111230231113
5212420304312043
610254152011303
71010130621312
oct151225545527
940426037203
1014132104023
115aa2227a14
1228a4990b33
131442ab323b
14980c63979
1557aa2a133
hex34a56cb57

14132104023 has 8 divisors (see below), whose sum is σ = 18848263536. Its totient is φ = 9418673600.

The previous prime is 14132103991. The next prime is 14132104027. The reversal of 14132104023 is 32040123141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14132104023 - 25 = 14132103991 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14132104027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 670158 + ... + 690923.

It is an arithmetic number, because the mean of its divisors is an integer number (2356032942).

Almost surely, 214132104023 is an apocalyptic number.

14132104023 is a deficient number, since it is larger than the sum of its proper divisors (4716159513).

14132104023 is a wasteful number, since it uses less digits than its factorization.

14132104023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1364545.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14132104023 its reverse (32040123141), we get a palindrome (46172227164).

The spelling of 14132104023 in words is "fourteen billion, one hundred thirty-two million, one hundred four thousand, twenty-three".

Divisors: 1 3 3461 10383 1361081 4083243 4710701341 14132104023