141321204131 has 2 divisors, whose sum is σ = 141321204132. Its totient is φ = 141321204130.

The previous prime is 141321204103. The next prime is 141321204161. The reversal of 141321204131 is 131402123141.

141321204131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (131402123141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141321204131 - 2¹⁴ = 141321187747 is a prime.

It is a super-2 number, since 2×141321204131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141321204097 and 141321204106.

It is not a weakly prime, because it can be changed into another prime (141321204161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70660602065 + 70660602066.

It is an arithmetic number, because the mean of its divisors is an integer number (70660602066).

Almost surely, 2^141321204131 is an apocalyptic number.

141321204131 is a deficient number, since it is larger than the sum of its proper divisors (1).

141321204131 is an equidigital number, since it uses as much as digits as its factorization.

141321204131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 141321204131 its reverse (131402123141), we get a palindrome (272723327272).

The spelling of 141321204131 in words is "one hundred forty-one billion, three hundred twenty-one million, two hundred four thousand, one hundred thirty-one".