Base | Representation |
---|---|
bin | 100000001000100000010111… |
… | …111011100111011010010001 |
3 | 200112101020210112122201110002 |
4 | 200020200113323213122101 |
5 | 122010404431341131343 |
6 | 1220322233311015345 |
7 | 41524115015625155 |
oct | 4010402773473221 |
9 | 615336715581402 |
10 | 141322005411473 |
11 | 41036364885807 |
12 | 13a2519980a555 |
13 | 60b17b9802c73 |
14 | 26c8043225065 |
15 | 115119a25d8b8 |
hex | 808817ee7691 |
141322005411473 has 2 divisors, whose sum is σ = 141322005411474. Its totient is φ = 141322005411472.
The previous prime is 141322005411439. The next prime is 141322005411581. The reversal of 141322005411473 is 374114500223141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 87157292341249 + 54164713070224 = 9335807^2 + 7359668^2 .
It is a cyclic number.
It is not a de Polignac number, because 141322005411473 - 212 = 141322005407377 is a prime.
It is not a weakly prime, because it can be changed into another prime (141322005411403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70661002705736 + 70661002705737.
It is an arithmetic number, because the mean of its divisors is an integer number (70661002705737).
Almost surely, 2141322005411473 is an apocalyptic number.
It is an amenable number.
141322005411473 is a deficient number, since it is larger than the sum of its proper divisors (1).
141322005411473 is an equidigital number, since it uses as much as digits as its factorization.
141322005411473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 38.
The spelling of 141322005411473 in words is "one hundred forty-one trillion, three hundred twenty-two billion, five million, four hundred eleven thousand, four hundred seventy-three".
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