Base | Representation |
---|---|
bin | 100000001000100000010111… |
… | …111011100111011001101111 |
3 | 200112101020210112122201101211 |
4 | 200020200113323213121233 |
5 | 122010404431341131224 |
6 | 1220322233311015251 |
7 | 41524115015625106 |
oct | 4010402773473157 |
9 | 615336715581354 |
10 | 141322005411439 |
11 | 41036364885786 |
12 | 13a2519980a527 |
13 | 60b17b9802c48 |
14 | 26c804322503d |
15 | 115119a25d894 |
hex | 808817ee766f |
141322005411439 has 2 divisors, whose sum is σ = 141322005411440. Its totient is φ = 141322005411438.
The previous prime is 141322005411427. The next prime is 141322005411473. The reversal of 141322005411439 is 934114500223141.
141322005411439 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141322005411439 - 223 = 141321997022831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141322005421439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70661002705719 + 70661002705720.
It is an arithmetic number, because the mean of its divisors is an integer number (70661002705720).
Almost surely, 2141322005411439 is an apocalyptic number.
141322005411439 is a deficient number, since it is larger than the sum of its proper divisors (1).
141322005411439 is an equidigital number, since it uses as much as digits as its factorization.
141322005411439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 40.
The spelling of 141322005411439 in words is "one hundred forty-one trillion, three hundred twenty-two billion, five million, four hundred eleven thousand, four hundred thirty-nine".
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