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141330403243321 is a prime number
BaseRepresentation
bin100000001000101000001100…
…011110110011010100111001
3200112102001110210122210001021
4200020220030132303110321
5122011024131212241241
61220330142501422441
741524533100210015
oct4010501436632471
9615361423583037
10141330403243321
1141039984178106
1213a2694210aa21
1360b25275a8836
1426c85dc68b545
1511514dc6400d1
hex808a0c7b3539

141330403243321 has 2 divisors, whose sum is σ = 141330403243322. Its totient is φ = 141330403243320.

The previous prime is 141330403243313. The next prime is 141330403243331. The reversal of 141330403243321 is 123342304033141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138252445286400 + 3077957956921 = 11758080^2 + 1754411^2 .

It is a cyclic number.

It is not a de Polignac number, because 141330403243321 - 23 = 141330403243313 is a prime.

It is a super-2 number, since 2×1413304032433212 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141330403243331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70665201621660 + 70665201621661.

It is an arithmetic number, because the mean of its divisors is an integer number (70665201621661).

Almost surely, 2141330403243321 is an apocalyptic number.

It is an amenable number.

141330403243321 is a deficient number, since it is larger than the sum of its proper divisors (1).

141330403243321 is an equidigital number, since it uses as much as digits as its factorization.

141330403243321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 141330403243321 its reverse (123342304033141), we get a palindrome (264672707276462).

The spelling of 141330403243321 in words is "one hundred forty-one trillion, three hundred thirty billion, four hundred three million, two hundred forty-three thousand, three hundred twenty-one".