141330403243331 has 2 divisors, whose sum is σ = 141330403243332. Its totient is φ = 141330403243330.

The previous prime is 141330403243321. The next prime is 141330403243333. The reversal of 141330403243331 is 133342304033141.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141330403243331 is a prime.

It is a super-2 number, since 2×141330403243331² (a number of 29 digits) contains 22 as substring.

Together with 141330403243333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 141330403243291 and 141330403243300.

It is not a weakly prime, because it can be changed into another prime (141330403243333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70665201621665 + 70665201621666.

It is an arithmetic number, because the mean of its divisors is an integer number (70665201621666).

Almost surely, 2^{141330403243331} is an apocalyptic number.

141330403243331 is a deficient number, since it is larger than the sum of its proper divisors (1).

141330403243331 is an equidigital number, since it uses as much as digits as its factorization.

141330403243331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 141330403243331 its reverse (133342304033141), we get a palindrome (274672707276472).

The spelling of 141330403243331 in words is "one hundred forty-one trillion, three hundred thirty billion, four hundred three million, two hundred forty-three thousand, three hundred thirty-one".