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14133114544151 is a prime number
BaseRepresentation
bin1100110110101001111101…
…0001011010000000010111
31212001010001001102102202102
43031222133101122000113
53323024104310403101
650020355125432315
72656040516326421
oct315523721320027
955033031372672
1014133114544151
11455990278a949
12170311356b69b
137b69931767c5
1436c091439811
1519797c3ce86b
hexcda9f45a017

14133114544151 has 2 divisors, whose sum is σ = 14133114544152. Its totient is φ = 14133114544150.

The previous prime is 14133114544117. The next prime is 14133114544169. The reversal of 14133114544151 is 15144541133141.

14133114544151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14133114544151 - 210 = 14133114543127 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14133114540151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066557272075 + 7066557272076.

It is an arithmetic number, because the mean of its divisors is an integer number (7066557272076).

Almost surely, 214133114544151 is an apocalyptic number.

14133114544151 is a deficient number, since it is larger than the sum of its proper divisors (1).

14133114544151 is an equidigital number, since it uses as much as digits as its factorization.

14133114544151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 57600, while the sum is 38.

Adding to 14133114544151 its reverse (15144541133141), we get a palindrome (29277655677292).

The spelling of 14133114544151 in words is "fourteen trillion, one hundred thirty-three billion, one hundred fourteen million, five hundred forty-four thousand, one hundred fifty-one".