1413334333141 has 4 divisors (see below), whose sum is σ = 1447805902284. Its totient is φ = 1378862764000.

The previous prime is 1413334333129. The next prime is 1413334333153.

1413334333141 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1413334333129) and next prime (1413334333153).

It can be written as a sum of positive squares in 2 ways, for example, as 619014900625 + 794319432516 = 786775^2 + 891246^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413334333141 - 2¹⁷ = 1413334202069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1413334333097 and 1413334333106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1413334333181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17235784510 + ... + 17235784591.

It is an arithmetic number, because the mean of its divisors is an integer number (361951475571).

Almost surely, 2^{1413334333141} is an apocalyptic number.

It is an amenable number.

1413334333141 is a deficient number, since it is larger than the sum of its proper divisors (34471569143).

1413334333141 is an equidigital number, since it uses as much as digits as its factorization.

1413334333141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34471569142.

The product of its digits is 46656, while the sum is 34.

The spelling of 1413334333141 in words is "one trillion, four hundred thirteen billion, three hundred thirty-four million, three hundred thirty-three thousand, one hundred forty-one".