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1413341946761 is a prime number
BaseRepresentation
bin10100100100010001101…
…111101010001110001001
312000010002020012220201012
4110210101233222032021
5141124011014244021
63001140314533305
7204052634221013
oct24442157521611
95003066186635
101413341946761
114a5438757378
121a9ab9437235
13a337baa2324
144c5985471b3
1526b6e60935b
hex14911bea389

1413341946761 has 2 divisors, whose sum is σ = 1413341946762. Its totient is φ = 1413341946760.

The previous prime is 1413341946733. The next prime is 1413341946763. The reversal of 1413341946761 is 1676491433141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1221809676025 + 191532270736 = 1105355^2 + 437644^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413341946761 - 26 = 1413341946697 is a prime.

It is a super-2 number, since 2×14133419467612 (a number of 25 digits) contains 22 as substring.

Together with 1413341946763, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1413341946763) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706670973380 + 706670973381.

It is an arithmetic number, because the mean of its divisors is an integer number (706670973381).

Almost surely, 21413341946761 is an apocalyptic number.

It is an amenable number.

1413341946761 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413341946761 is an equidigital number, since it uses as much as digits as its factorization.

1413341946761 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1306368, while the sum is 50.

The spelling of 1413341946761 in words is "one trillion, four hundred thirteen billion, three hundred forty-one million, nine hundred forty-six thousand, seven hundred sixty-one".