Base | Representation |
---|---|
bin | 100000001000101011101111… |
… | …111111110011110100000111 |
3 | 200112102102022211011120111120 |
4 | 200020223233333303310013 |
5 | 122011104440400332403 |
6 | 1220332013335005023 |
7 | 41525026506646302 |
oct | 4010535777636407 |
9 | 615372284146446 |
10 | 141334220324103 |
11 | 41040562885424 |
12 | 13a27628509773 |
13 | 60b29b5343711 |
14 | 26c88815c7b39 |
15 | 11516627d1e53 |
hex | 808aefff3d07 |
141334220324103 has 4 divisors (see below), whose sum is σ = 188445627098808. Its totient is φ = 94222813549400.
The previous prime is 141334220324083. The next prime is 141334220324119. The reversal of 141334220324103 is 301423022433141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141334220324103 - 29 = 141334220323591 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141334220324503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23555703387348 + ... + 23555703387353.
It is an arithmetic number, because the mean of its divisors is an integer number (47111406774702).
Almost surely, 2141334220324103 is an apocalyptic number.
141334220324103 is a deficient number, since it is larger than the sum of its proper divisors (47111406774705).
141334220324103 is an equidigital number, since it uses as much as digits as its factorization.
141334220324103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47111406774704.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 141334220324103 its reverse (301423022433141), we get a palindrome (442757242757244).
The spelling of 141334220324103 in words is "one hundred forty-one trillion, three hundred thirty-four billion, two hundred twenty million, three hundred twenty-four thousand, one hundred three".
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