141336202633141 has 2 divisors, whose sum is σ = 141336202633142. Its totient is φ = 141336202633140.

The previous prime is 141336202633079. The next prime is 141336202633159.

141336202633141 is nontrivially palindromic in base 10.

141336202633141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114530214130641 + 26805988502500 = 10701879^2 + 5177450^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 141336202633141 - 2¹⁹ = 141336202108853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141336202633094 and 141336202633103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141336202633541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70668101316570 + 70668101316571.

It is an arithmetic number, because the mean of its divisors is an integer number (70668101316571).

Almost surely, 2^{141336202633141} is an apocalyptic number.

It is an amenable number.

141336202633141 is a deficient number, since it is larger than the sum of its proper divisors (1).

141336202633141 is an equidigital number, since it uses as much as digits as its factorization.

141336202633141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 186624, while the sum is 40.

It can be divided in two parts, 14133620 and 2633141, that added together give a palindrome (16766761).

The spelling of 141336202633141 in words is "one hundred forty-one trillion, three hundred thirty-six billion, two hundred two million, six hundred thirty-three thousand, one hundred forty-one".