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14134000433 = 717033118543
BaseRepresentation
bin11010010100111001…
…11011101100110001
31100111000121121121112
431022130323230301
5212421301003213
610254300403105
71010153010230
oct151234735461
940430547545
1014134000433
115aa33027a3
1228a5546495
1314432c8487
149811d8b17
1557aca1ea8
hex34a73bb31

14134000433 has 8 divisors (see below), whose sum is σ = 16154227968. Its totient is φ = 12114044064.

The previous prime is 14134000373. The next prime is 14134000451. The reversal of 14134000433 is 33400043141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14134000433 - 216 = 14133934897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14134000399 and 14134000408.

It is not an unprimeable number, because it can be changed into a prime (14134000493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59960 + ... + 178502.

It is an arithmetic number, because the mean of its divisors is an integer number (2019278496).

Almost surely, 214134000433 is an apocalyptic number.

It is an amenable number.

14134000433 is a deficient number, since it is larger than the sum of its proper divisors (2020227535).

14134000433 is a wasteful number, since it uses less digits than its factorization.

14134000433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135583.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 14134000433 its reverse (33400043141), we get a palindrome (47534043574).

The spelling of 14134000433 in words is "fourteen billion, one hundred thirty-four million, four hundred thirty-three", and thus it is an aban number.

Divisors: 1 7 17033 118543 119231 829801 2019142919 14134000433