1413401311111 has 4 divisors (see below), whose sum is σ = 1458994901824. Its totient is φ = 1367807720400.

The previous prime is 1413401311109. The next prime is 1413401311139. The reversal of 1413401311111 is 1111131043141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1413401311111 - 2¹ = 1413401311109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1413401311711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22796795310 + ... + 22796795371.

It is an arithmetic number, because the mean of its divisors is an integer number (364748725456).

Almost surely, 2^{1413401311111} is an apocalyptic number.

1413401311111 is a deficient number, since it is larger than the sum of its proper divisors (45593590713).

1413401311111 is an equidigital number, since it uses as much as digits as its factorization.

1413401311111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45593590712.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 1413401311111 its reverse (1111131043141), we get a palindrome (2524532354252).

The spelling of 1413401311111 in words is "one trillion, four hundred thirteen billion, four hundred one million, three hundred eleven thousand, one hundred eleven".