Base | Representation |
---|---|
bin | 10100100100010101010… |
… | …010001010001100001011 |
3 | 12000010020100221111120102 |
4 | 110210111102022030023 |
5 | 141124121214303001 |
6 | 3001150235320015 |
7 | 204054255004262 |
oct | 24442522121413 |
9 | 5003210844512 |
10 | 1413401322251 |
11 | 4a5469221026 |
12 | 1a9b152b000b |
13 | a338b190c59 |
14 | 4c5a23a15d9 |
15 | 26b74936e6b |
hex | 1491548a30b |
1413401322251 has 2 divisors, whose sum is σ = 1413401322252. Its totient is φ = 1413401322250.
The previous prime is 1413401322227. The next prime is 1413401322313. The reversal of 1413401322251 is 1522231043141.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (1522231043141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1413401322251 - 226 = 1413334213387 is a prime.
It is not a weakly prime, because it can be changed into another prime (1413401322451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706700661125 + 706700661126.
It is an arithmetic number, because the mean of its divisors is an integer number (706700661126).
Almost surely, 21413401322251 is an apocalyptic number.
1413401322251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1413401322251 is an equidigital number, since it uses as much as digits as its factorization.
1413401322251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 1413401322251 its reverse (1522231043141), we get a palindrome (2935632365392).
The spelling of 1413401322251 in words is "one trillion, four hundred thirteen billion, four hundred one million, three hundred twenty-two thousand, two hundred fifty-one".
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