Base | Representation |
---|---|
bin | 100000001000110001011011… |
… | …101101100010111101101010 |
3 | 200112110000002002101100010101 |
4 | 200020301123231202331222 |
5 | 122011204440021134424 |
6 | 1220334503040340014 |
7 | 41525333644053604 |
oct | 4010613355427552 |
9 | 615400062340111 |
10 | 141340322443114 |
11 | 41043104314793 |
12 | 13a2885001460a |
13 | 60b3448615622 |
14 | 26c8c9dbba174 |
15 | 11518bd38c344 |
hex | 808c5bb62f6a |
141340322443114 has 4 divisors (see below), whose sum is σ = 212010483664674. Its totient is φ = 70670161221556.
The previous prime is 141340322443027. The next prime is 141340322443121. The reversal of 141340322443114 is 411344223043141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 119177723091025 + 22162599352089 = 10916855^2 + 4707717^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35335080610777 + ... + 35335080610780.
Almost surely, 2141340322443114 is an apocalyptic number.
141340322443114 is a deficient number, since it is larger than the sum of its proper divisors (70670161221560).
141340322443114 is an equidigital number, since it uses as much as digits as its factorization.
141340322443114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70670161221559.
The product of its (nonzero) digits is 110592, while the sum is 37.
Adding to 141340322443114 its reverse (411344223043141), we get a palindrome (552684545486255).
The spelling of 141340322443114 in words is "one hundred forty-one trillion, three hundred forty billion, three hundred twenty-two million, four hundred forty-three thousand, one hundred fourteen".
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