141340404121 has 4 divisors (see below), whose sum is σ = 161531890432. Its totient is φ = 121148917812.

The previous prime is 141340404119. The next prime is 141340404167. The reversal of 141340404121 is 121404043141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121404043141 = 4679 ⋅25946579.

It is a cyclic number.

It is not a de Polignac number, because 141340404121 - 2¹ = 141340404119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141340404721) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10095743145 + ... + 10095743158.

It is an arithmetic number, because the mean of its divisors is an integer number (40382972608).

Almost surely, 2^141340404121 is an apocalyptic number.

It is an amenable number.

141340404121 is a deficient number, since it is larger than the sum of its proper divisors (20191486311).

141340404121 is an equidigital number, since it uses as much as digits as its factorization.

141340404121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20191486310.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 141340404121 its reverse (121404043141), we get a palindrome (262744447262).

The spelling of 141340404121 in words is "one hundred forty-one billion, three hundred forty million, four hundred four thousand, one hundred twenty-one".